What is the moment contributed by the 10-pound weight located 4 feet aft of the CG, expressed in ft-lb?

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Multiple Choice

What is the moment contributed by the 10-pound weight located 4 feet aft of the CG, expressed in ft-lb?

Explanation:
Moment about the CG is found by multiplying the weight by its arm, the distance from the CG. Here the weight is 10 pounds and its arm is 4 feet, so the moment is 10 × 4 = 40 ft-lb. Because the weight sits aft of the CG, this downward force behind the CG creates a nose-up pitching moment. The magnitude is 40 ft-lb (the other numerical options would come from using different distances).

Moment about the CG is found by multiplying the weight by its arm, the distance from the CG. Here the weight is 10 pounds and its arm is 4 feet, so the moment is 10 × 4 = 40 ft-lb. Because the weight sits aft of the CG, this downward force behind the CG creates a nose-up pitching moment. The magnitude is 40 ft-lb (the other numerical options would come from using different distances).

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