If 60 gallons of fuel are burned (360 lb) from the baseline configuration, what is the new weight and CG?

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Multiple Choice

If 60 gallons of fuel are burned (360 lb) from the baseline configuration, what is the new weight and CG?

Explanation:
When fuel is burned, the aircraft’s weight drops by the amount burned, and the center of gravity shifts based on where that fuel was located. Here, 60 gallons weigh 360 lb, so the new weight equals the baseline weight minus 360 lb. If the baseline weight is 2,200 lb, removing 360 lb gives 1,840 lb. For the CG, use the moment balance: CG_new = (W0*CG0 − fuel_weight*CG_fuel) / (W0 − fuel_weight). If the removed fuel segment lies at the same general lever arm as the aircraft’s overall CG (or very close to it), the moment term changes in such a way that the CG doesn’t move much. In this case, the CG stays about the same, around 74 inches. Thus, the new weight is 1,840 lb and the CG remains approximately 74.0 inches, matching the given answer.

When fuel is burned, the aircraft’s weight drops by the amount burned, and the center of gravity shifts based on where that fuel was located. Here, 60 gallons weigh 360 lb, so the new weight equals the baseline weight minus 360 lb.

If the baseline weight is 2,200 lb, removing 360 lb gives 1,840 lb. For the CG, use the moment balance: CG_new = (W0CG0 − fuel_weightCG_fuel) / (W0 − fuel_weight). If the removed fuel segment lies at the same general lever arm as the aircraft’s overall CG (or very close to it), the moment term changes in such a way that the CG doesn’t move much. In this case, the CG stays about the same, around 74 inches.

Thus, the new weight is 1,840 lb and the CG remains approximately 74.0 inches, matching the given answer.

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