Given weight 1,840 lb and moment 136,080 in-lb, what is the CG approximately?

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Multiple Choice

Given weight 1,840 lb and moment 136,080 in-lb, what is the CG approximately?

Explanation:
The main idea is that the center of gravity along the forward‑aft axis is found by dividing the total moment by the total weight: CG = M / W. Here the total moment is 136,080 in-lb and the total weight is 1,840 lb. Compute: CG = 136,080 / 1,840 ≈ 73.96 inches, which is essentially 74 inches from the datum. The moment that would correspond to exactly 74 inches would be 1,840 × 74 = 136,160 in-lb, very close to the given moment, confirming the result. So the approximate CG is about 74 inches.

The main idea is that the center of gravity along the forward‑aft axis is found by dividing the total moment by the total weight: CG = M / W. Here the total moment is 136,080 in-lb and the total weight is 1,840 lb.

Compute: CG = 136,080 / 1,840 ≈ 73.96 inches, which is essentially 74 inches from the datum. The moment that would correspond to exactly 74 inches would be 1,840 × 74 = 136,160 in-lb, very close to the given moment, confirming the result.

So the approximate CG is about 74 inches.

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